## Where does pi R squared come from?

Math textbooks often present formulas, even extremely important ones, without proof or justification. That’s probably fine for the student with average interest and ability, but it is often a disservice to students who really want to understand the subject. My preference would be that the books have derivations in a sidebar, with the understanding that students will not be tested on that material, but it will be there for those students who want to understand the material on a deeper level.

An example of such a formula is the one for the area of a circle: . The formula was derived by Archimedes over 2,000 years ago; it is certainly one of the most useful results in mathematics. In spite of its fundamental importance, several high school math books that I have checked didn’t attempt to show where it comes from. In this post I will explain one way that the formula can be derived, and in other posts I will explain a number of other important formulas.

First, imagine that we divide the circle into equal-sized triangles as show below.

We can approximate the circle’s area by just computing the area of all the triangles. If there are *n* triangles, then \(\mbox{circle area }\approx n\cdot\frac{1}{2}bh \)

Now imagine we begin increasing the number of triangles. Two things will happen:

- The area approximation will become closer and closer to the real value
- The altitude h of each triangle will become arbitrarily close to R, the circles radius.

So

\[\mbox{circle area}\approx\:n\:\cdot\:\frac{1}{2}\,bR,\:or\:\frac{1}{2}\,R\:\cdot\:nb. \]

Notice the product *nb* – for very large n, this become the same as the circumference of the circle, or \(2\pi R\)

If we replace *nb* in the above formula, we finally have,

\[\mbox{circle area}\approx\:\frac{1}{2}\,R\,\cdot\,2\pi\,R\:=\:\pi\,R^{2} \]

So, as n becomes infinite, the area actually *becomes* \(\pi R^{2} \)

Now, for those who have been exposed to only algebra and geometry, the type of reasoning used here may seem strange. We are taking an infinite number of triangles, each infinitely small, and coming up with a finite number – the exact area of the circle.

This is basically what the subject of integral calculus is about. Integral calculus provides very general and powerful methods for computing areas. And it’s not just about finding areas of geometric shapes – an amazing number of useful problems, if thought of the right way, are equivalent to the problem of finding an area.

Calculus was not invented until the late 1600’s, so Archimedes couldn’t use it in deriving the circle area formula. The method he actually used was roughly equivalent to the derivation used here.

January 10th, 2010 at 11:50 am

oh my god!!! this is such a lifesaver!!!! this is exactly what i need!!! thanks a lot for posting this!!! :D:D:D:D

May 1st, 2012 at 9:11 pm

Great Info really helped

June 7th, 2012 at 11:23 pm

Huh??? Too long and wordy. http://www.youtube.com/watch?v=whYqhpc6S6g This video is better in explaning!

June 21st, 2012 at 9:54 am

thank you it is very helpful.

you should show a couple of example of how to go form nb to 2?R.

June 21st, 2012 at 3:48 pm

What we are doing here is approximating the circle with a polygon having n sides. Each side of the polygon has a length of b, so its perimeter is nb. This is less than the circumference of the circle, but it becomes closer and closer as n is increased.

The circumference of the circle is exactly 2* pi * r, so nb is approaching this value for large n.

February 6th, 2013 at 7:55 pm

Excellent description….

April 2nd, 2013 at 1:40 am

Good! Very good indeed! A clear, concise, easy to follow explanation.

And I like the way you tie it to integral calculus. Keep up the good work.